Curriculum›4A›Chapter 1

Calculations and Place Value

4A · Chapter 1 · Lesson 7 · MATH-4A-C01-L07

Learning goal. Use powers-of-ten place shifts and decompositions to calculate without changing quantities.

Before you begin

Recall: Grade 3: four-digit place value, regrouping, comparison and rounding; Rounding 6-Digit Numbers. Try these three warm-up problems. If they are difficult, revisit the prerequisite lesson before advancing.

Question 1 · calculation

Round 344,142 to the nearest 1,000.

Show answer & reasoning
344,000

The bounding multiples are 344,000 and 345,000. The midpoint is 344,500, so the nearer benchmark is 344,000.

Question 2 · reasoning

What is the midpoint between 816,000 and 817,000?

Show answer & reasoning
816,500

Half of the interval of 1,000 is 500. Add it to the lower benchmark.

Question 3 · explanation

Explain why rounding 401,224 to the nearest 1,000 gives 401,000.

Show answer & reasoning
401,000

401,224 is between 401,000 and 402,000; the midpoint is 401,500.

Key vocabulary

place value
value determined by a digit position
expanded form
sum of each nonzero place value
benchmark
nearby convenient multiple
midpoint
number exactly halfway between two bounds

Understand the concept

Place value lets you compute with groups of tens, hundreds and thousands instead of treating long numerals as indivisible strings. Multiplying by 100 scales every unit one hundredfold; adding 3 thousands changes the number by exactly 3,000. Show the equivalent expanded forms and explain each exchange before relying on a written shortcut.

100,000← ×1010,000← ×101,000← ×10100← ×1010← ×101ones

Model it: place-value arrows and expanded-form regrouping. Explain what every part of the model represents, then write a matching equation.

Fully worked examples

Read the problem first and predict the answer. Then study how each quantity is represented and calculated.

Worked example 1

Question 1 · calculation

Calculate 5,862 × 10 using place value.

Answer: 58,620

Every place-value unit becomes 10 times as large; 5,862 × 10 = 58,620.

Check your understanding 1

Question 1 · calculation

Calculate 4,343 × 10 using place value.

Show answer & reasoning
43,430

Every place-value unit becomes 10 times as large; 4,343 × 10 = 43,430.

Worked example 2

Question 2 · calculation

Calculate 5,325 × 100 using place value.

Answer: 532,500

Every place-value unit becomes 100 times as large; 5,325 × 100 = 532,500.

Check your understanding 2

Question 2 · calculation

Calculate 3,233 × 10 using place value.

Show answer & reasoning
32,330

Every place-value unit becomes 10 times as large; 3,233 × 10 = 32,330.

Worked example 3

Question 3 · calculation

Calculate 180,560 ÷ 10 by grouping place-value units.

Answer: 18,056

Dividing by 10 reduces each place-value unit by a factor of 10. The quotient is 18,056.

Check your understanding 3

Question 3 · calculation

Calculate 167,660 ÷ 10 by grouping place-value units.

Show answer & reasoning
16,766

Dividing by 10 reduces each place-value unit by a factor of 10. The quotient is 16,766.

Guided practice

Question 1 · calculation

Calculate 6,888 × 100 using place value.

Show answer & reasoning
688,800

Every place-value unit becomes 100 times as large; 6,888 × 100 = 688,800.

Question 2 · calculation

Calculate 8,252 × 100 using place value.

Show answer & reasoning
825,200

Every place-value unit becomes 100 times as large; 8,252 × 100 = 825,200.

Question 3 · calculation

Calculate 728,600 ÷ 100 by grouping place-value units.

Show answer & reasoning
7,286

Dividing by 100 reduces each place-value unit by a factor of 100. The quotient is 7,286.

Question 4 · explanation

Find 50,809 + 10,000. Explain which place-value units change.

Show answer & reasoning
60,809

Adding 10,000 increases the number by that place-value unit, with exchanges if needed: 60,809.

Question 5 · application

A teacher partitions 16,350 counters into equal groups of 10. How many counters are in each group?

Show answer & reasoning
1,635

Each group has 16,350 ÷ 10 = 1,635 counters.

Independent practice

Question 1 · calculation

Calculate 9,546 × 10 using place value.

Show answer & reasoning
95,460

Every place-value unit becomes 10 times as large; 9,546 × 10 = 95,460.

Question 2 · calculation

Calculate 340,100 ÷ 100 by grouping place-value units.

Show answer & reasoning
3,401

Dividing by 100 reduces each place-value unit by a factor of 100. The quotient is 3,401.

Question 3 · explanation

Find 29,000 + 1,000. Explain which place-value units change.

Show answer & reasoning
30,000

Adding 1,000 increases the number by that place-value unit, with exchanges if needed: 30,000.

Question 4 · application

A teacher partitions 45,150 counters into equal groups of 10. How many counters are in each group?

Show answer & reasoning
4,515

Each group has 45,150 ÷ 10 = 4,515 counters.

Question 5 · strategy

Calculate 48,795 + 4,142 and check by subtraction.

Show answer & reasoning
52,937

48,795 + 4,142 = 52,937; subtract 4,142 to recover 48,795.

Question 6 · calculation

Calculate 16,839 × 10 using place value.

Show answer & reasoning
168,390

Every place-value unit becomes 10 times as large; 16,839 × 10 = 168,390.

Question 7 · calculation

Calculate 14,357 × 10 using place value.

Show answer & reasoning
143,570

Every place-value unit becomes 10 times as large; 14,357 × 10 = 143,570.

Question 8 · calculation

Calculate 97,610 ÷ 10 by grouping place-value units.

Show answer & reasoning
9,761

Dividing by 10 reduces each place-value unit by a factor of 10. The quotient is 9,761.

Challenge and transfer

Explain the relationships and justify your method. Multiple correct approaches may be accepted if the reasoning is valid.

Question 1 · error analysis

A learner multiplies 5,500 by 100 and writes 55,000. Identify the scaling mistake and give the correct result.

Show answer & reasoning
550,000

Multiplying by 100 makes every place value one hundred times larger. The correct product is 550,000.

Question 2 · strategy

Calculate 46,668 + 3,456 and check by subtraction.

Show answer & reasoning
50,124

46,668 + 3,456 = 50,124; subtract 3,456 to recover 46,668.

Exit check

Question 1 · explanation

Find 76,193 + 1,000. Explain which place-value units change.

Show answer & reasoning
77,193

Adding 1,000 increases the number by that place-value unit, with exchanges if needed: 77,193.

Question 2 · application

A teacher partitions 68,520 counters into equal groups of 10. How many counters are in each group?

Show answer & reasoning
6,852

Each group has 68,520 ÷ 10 = 6,852 counters.

Question 3 · strategy

Calculate 36,044 + 2,582 and check by subtraction.

Show answer & reasoning
38,626

36,044 + 2,582 = 38,626; subtract 2,582 to recover 36,044.

Self-check: Revisit any item you cannot explain without looking at the answer. Return later and solve a fresh version to confirm retention.