Curriculum›4A›Chapter 4

Multiplying by a 1-Digit Number — Part 2

4A · Chapter 4 · Lesson 3 · MATH-4A-C04-L03

Learning goal. Coordinate successive regroupings and verify products by magnitude estimation.

Before you begin

Recall: Grade 3: multidigit × one digit, arrays; 4A Ch3: multiples; Multiplying by a 1-Digit Number — Part 1. Try these three warm-up problems. If they are difficult, revisit the prerequisite lesson before advancing.

Question 1 · calculation

Calculate 36 × 7.

Show answer & reasoning
252

36 × 7 = (30 × 7) + (6 × 7) = 252. Each partial product uses its correct place value.

Question 2 · calculation

Calculate 46 × 3.

Show answer & reasoning
138

46 × 3 = (40 × 3) + (6 × 3) = 138. Each partial product uses its correct place value.

Question 3 · calculation

Calculate 50 × 9.

Show answer & reasoning
450

50 × 9 = (50 × 9) + (0 × 9) = 450. Each partial product uses its correct place value.

Key vocabulary

partial product
product of one part of each decomposed factor
distributive property
multiplication distributed across a sum
area model
rectangular representation of a product
regroup
exchange ten small units for one larger unit

Understand the concept

Successive regrouping requires attention to each exchanged unit. For 286 × 7, seven sixes make 42 ones: write two ones and exchange four tens. Then include those four tens when multiplying the tens column. Estimate first: about 300 × 7 = 2,100, so a three-digit answer would be suspicious.

200406012204103

Model it: hundreds–tens–ones exchange chart. Explain what every part of the model represents, then write a matching equation.

Fully worked examples

Read the problem first and predict the answer. Then study how each quantity is represented and calculated.

Worked example 1

Question 1 · calculation

Calculate 110 × 2.

Answer: 220

110 × 2 = (110 × 2) + (0 × 2) = 220. Each partial product uses its correct place value.

Check your understanding 1

Question 1 · calculation

Calculate 38 × 4.

Show answer & reasoning
152

38 × 4 = (30 × 4) + (8 × 4) = 152. Each partial product uses its correct place value.

Worked example 2

Question 2 · calculation

Calculate 66 × 7.

Answer: 462

66 × 7 = (60 × 7) + (6 × 7) = 462. Each partial product uses its correct place value.

Check your understanding 2

Question 2 · calculation

Calculate 191 × 4.

Show answer & reasoning
764

191 × 4 = (190 × 4) + (1 × 4) = 764. Each partial product uses its correct place value.

Worked example 3

Question 3 · calculation

Calculate 71 × 9.

Answer: 639

71 × 9 = (70 × 9) + (1 × 9) = 639. Each partial product uses its correct place value.

Check your understanding 3

Question 3 · calculation

Calculate 47 × 2.

Show answer & reasoning
94

47 × 2 = (40 × 2) + (7 × 2) = 94. Each partial product uses its correct place value.

Guided practice

Question 1 · calculation

Calculate 164 × 9.

Show answer & reasoning
1,476

164 × 9 = (160 × 9) + (4 × 9) = 1476. Each partial product uses its correct place value.

Question 2 · calculation

Calculate 120 × 5.

Show answer & reasoning
600

120 × 5 = (120 × 5) + (0 × 5) = 600. Each partial product uses its correct place value.

Question 3 · calculation

Calculate 186 × 4.

Show answer & reasoning
744

186 × 4 = (180 × 4) + (6 × 4) = 744. Each partial product uses its correct place value.

Question 4 · calculation

Calculate 17 × 4.

Show answer & reasoning
68

17 × 4 = (10 × 4) + (7 × 4) = 68. Each partial product uses its correct place value.

Question 5 · calculation

Calculate 143 × 3.

Show answer & reasoning
429

143 × 3 = (140 × 3) + (3 × 3) = 429. Each partial product uses its correct place value.

Independent practice

Question 1 · calculation

Calculate 85 × 9.

Show answer & reasoning
765

85 × 9 = (80 × 9) + (5 × 9) = 765. Each partial product uses its correct place value.

Question 2 · calculation

Calculate 36 × 6.

Show answer & reasoning
216

36 × 6 = (30 × 6) + (6 × 6) = 216. Each partial product uses its correct place value.

Question 3 · calculation

Calculate 129 × 7.

Show answer & reasoning
903

129 × 7 = (120 × 7) + (9 × 7) = 903. Each partial product uses its correct place value.

Question 4 · calculation

Calculate 140 × 5.

Show answer & reasoning
700

140 × 5 = (140 × 5) + (0 × 5) = 700. Each partial product uses its correct place value.

Question 5 · calculation

Calculate 167 × 8.

Show answer & reasoning
1,336

167 × 8 = (160 × 8) + (7 × 8) = 1336. Each partial product uses its correct place value.

Question 6 · calculation

Calculate 197 × 5.

Show answer & reasoning
985

197 × 5 = (190 × 5) + (7 × 5) = 985. Each partial product uses its correct place value.

Question 7 · calculation

Calculate 48 × 8.

Show answer & reasoning
384

48 × 8 = (40 × 8) + (8 × 8) = 384. Each partial product uses its correct place value.

Question 8 · calculation

Calculate 186 × 5.

Show answer & reasoning
930

186 × 5 = (180 × 5) + (6 × 5) = 930. Each partial product uses its correct place value.

Challenge and transfer

Explain the relationships and justify your method. Multiple correct approaches may be accepted if the reasoning is valid.

Question 1 · error analysis

A student calculates 43 × 4 using only its tens: 40 × 4. What partial product is missing and what is the correct total?

Show answer & reasoning
172

The ones part 3 × 4 = 12 must also be included. The complete product is 172.

Question 2 · calculation

Calculate 88 × 8.

Show answer & reasoning
704

88 × 8 = (80 × 8) + (8 × 8) = 704. Each partial product uses its correct place value.

Exit check

Question 1 · calculation

Calculate 31 × 6.

Show answer & reasoning
186

31 × 6 = (30 × 6) + (1 × 6) = 186. Each partial product uses its correct place value.

Question 2 · calculation

Calculate 77 × 6.

Show answer & reasoning
462

77 × 6 = (70 × 6) + (7 × 6) = 462. Each partial product uses its correct place value.

Question 3 · calculation

Calculate 182 × 8.

Show answer & reasoning
1,456

182 × 8 = (180 × 8) + (2 × 8) = 1456. Each partial product uses its correct place value.

Self-check: Revisit any item you cannot explain without looking at the answer. Return later and solve a fresh version to confirm retention.