Curriculum›4A›Chapter 4

Multiplying by a 1-Digit Number — Part 1

4A · Chapter 4 · Lesson 2 · MATH-4A-C04-L02

Learning goal. Explain multi-place one-digit multiplication using partial products before regrouping.

Before you begin

Recall: Grade 3: multidigit × one digit, arrays; 4A Ch3: multiples; Mental Math for Multiplication. Try these three warm-up problems. If they are difficult, revisit the prerequisite lesson before advancing.

Question 1 · calculation

Calculate 26 × 7 using a split or friendly number.

Show answer & reasoning
182

Split 26 into 20 + 6. Then multiply each part by 7 and add the partial products.

Question 2 · calculation

Calculate 25 × 7 using a split or friendly number.

Show answer & reasoning
175

Split 25 into 20 + 5. Then multiply each part by 7 and add the partial products.

Question 3 · calculation

Calculate 87 × 2 using a split or friendly number.

Show answer & reasoning
174

Split 87 into 80 + 7. Then multiply each part by 2 and add the partial products.

Key vocabulary

partial product
product of one part of each decomposed factor
distributive property
multiplication distributed across a sum
area model
rectangular representation of a product
regroup
exchange ten small units for one larger unit

Understand the concept

Multiplying a two- or three-digit number by one digit means multiplying each place-value part. For 213 × 4, calculate 200×4, 10×4 and 3×4, then combine 800+40+12. A written algorithm compresses the same reasoning, but the place values remain the foundation.

200406012204103

Model it: partial-products area partition. Explain what every part of the model represents, then write a matching equation.

Fully worked examples

Read the problem first and predict the answer. Then study how each quantity is represented and calculated.

Worked example 1

Question 1 · calculation

Calculate 78 × 2.

Answer: 156

78 × 2 = (70 × 2) + (8 × 2) = 156. Each partial product uses its correct place value.

Check your understanding 1

Question 1 · calculation

Calculate 85 × 4.

Show answer & reasoning
340

85 × 4 = (80 × 4) + (5 × 4) = 340. Each partial product uses its correct place value.

Worked example 2

Question 2 · calculation

Calculate 41 × 6.

Answer: 246

41 × 6 = (40 × 6) + (1 × 6) = 246. Each partial product uses its correct place value.

Check your understanding 2

Question 2 · calculation

Calculate 76 × 4.

Show answer & reasoning
304

76 × 4 = (70 × 4) + (6 × 4) = 304. Each partial product uses its correct place value.

Worked example 3

Question 3 · calculation

Calculate 66 × 9.

Answer: 594

66 × 9 = (60 × 9) + (6 × 9) = 594. Each partial product uses its correct place value.

Check your understanding 3

Question 3 · calculation

Calculate 34 × 3.

Show answer & reasoning
102

34 × 3 = (30 × 3) + (4 × 3) = 102. Each partial product uses its correct place value.

Guided practice

Question 1 · calculation

Calculate 27 × 7.

Show answer & reasoning
189

27 × 7 = (20 × 7) + (7 × 7) = 189. Each partial product uses its correct place value.

Question 2 · calculation

Calculate 84 × 2.

Show answer & reasoning
168

84 × 2 = (80 × 2) + (4 × 2) = 168. Each partial product uses its correct place value.

Question 3 · calculation

Calculate 95 × 9.

Show answer & reasoning
855

95 × 9 = (90 × 9) + (5 × 9) = 855. Each partial product uses its correct place value.

Question 4 · calculation

Calculate 92 × 6.

Show answer & reasoning
552

92 × 6 = (90 × 6) + (2 × 6) = 552. Each partial product uses its correct place value.

Question 5 · calculation

Calculate 42 × 9.

Show answer & reasoning
378

42 × 9 = (40 × 9) + (2 × 9) = 378. Each partial product uses its correct place value.

Independent practice

Question 1 · calculation

Calculate 98 × 9.

Show answer & reasoning
882

98 × 9 = (90 × 9) + (8 × 9) = 882. Each partial product uses its correct place value.

Question 2 · calculation

Calculate 48 × 3.

Show answer & reasoning
144

48 × 3 = (40 × 3) + (8 × 3) = 144. Each partial product uses its correct place value.

Question 3 · calculation

Calculate 86 × 6.

Show answer & reasoning
516

86 × 6 = (80 × 6) + (6 × 6) = 516. Each partial product uses its correct place value.

Question 4 · calculation

Calculate 88 × 8.

Show answer & reasoning
704

88 × 8 = (80 × 8) + (8 × 8) = 704. Each partial product uses its correct place value.

Question 5 · calculation

Calculate 20 × 4.

Show answer & reasoning
80

20 × 4 = (20 × 4) + (0 × 4) = 80. Each partial product uses its correct place value.

Question 6 · calculation

Calculate 63 × 2.

Show answer & reasoning
126

63 × 2 = (60 × 2) + (3 × 2) = 126. Each partial product uses its correct place value.

Question 7 · calculation

Calculate 41 × 7.

Show answer & reasoning
287

41 × 7 = (40 × 7) + (1 × 7) = 287. Each partial product uses its correct place value.

Question 8 · calculation

Calculate 32 × 5.

Show answer & reasoning
160

32 × 5 = (30 × 5) + (2 × 5) = 160. Each partial product uses its correct place value.

Challenge and transfer

Explain the relationships and justify your method. Multiple correct approaches may be accepted if the reasoning is valid.

Question 1 · error analysis

A student calculates 44 × 6 using only its tens: 40 × 6. What partial product is missing and what is the correct total?

Show answer & reasoning
264

The ones part 4 × 6 = 24 must also be included. The complete product is 264.

Question 2 · calculation

Calculate 59 × 6.

Show answer & reasoning
354

59 × 6 = (50 × 6) + (9 × 6) = 354. Each partial product uses its correct place value.

Exit check

Question 1 · calculation

Calculate 80 × 8.

Show answer & reasoning
640

80 × 8 = (80 × 8) + (0 × 8) = 640. Each partial product uses its correct place value.

Question 2 · calculation

Calculate 69 × 4.

Show answer & reasoning
276

69 × 4 = (60 × 4) + (9 × 4) = 276. Each partial product uses its correct place value.

Question 3 · calculation

Calculate 90 × 2.

Show answer & reasoning
180

90 × 2 = (90 × 2) + (0 × 2) = 180. Each partial product uses its correct place value.

Self-check: Revisit any item you cannot explain without looking at the answer. Return later and solve a fresh version to confirm retention.